A rectangular prism has a height of 12 centimeters and a square base with sides measuring 5 centimeters. A pyramid with the same base and half the height of the prism is placed inside the prism, as shown in the figure

The answer is 200 cm³

The volume of the rectangular prism (V1) is:

V1 = l · w · h                       (l - length,  w - width,  h - height)

It is given:

h = 12 cm

w = l = 5 cm (since it has a square base which all sides are the same size).

Thus: V1 = 12 · 5 · 5 = 300 cm³

The volume of pyramid (V2) is:

V2 = 1/3 · l · w · h                   (l - length,  w - width,  h - height)

It is given:

h = 12 cm

w = l = 5 cm (since it has a square base which all sides are the same size).

V2 = 1/3 · 12 · 5 · 5 = 1/3 · 300 = 100 cm³

The volume of the space outside the pyramid but inside the prism (V) is a difference between the volume of the rectangular prism (V1) and the volume of the pyramid (V2):  

V = V1 - V2 = 300 cm³ - 100 cm³ = 200 cm³

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