when a 200 g solution A and 400g of saline solution B are mixed a 6% salt solution is created also when a 400g of saline solution A and 200g of solution B are mixed 7% salt is created find what percent concentration of saline and saline b solution are

A = 8%, B = 5%

Step-by-step explanation:

Let

a=concentration of solution A (in percent)

b=concentration of solution B (in percent)

Given

2a+4b = 0.06*(2+4)  (1)

4a+2b = 0.07*(4+2)  (2)

2(1) - (2)

4a-4a +8b-2b = 6 (2*0.06-0.07)

6b = 6(0.05)

b = 0.05  (3)

Substitute (3) into (1) and solve for a

2a+4(0.05) = 0.36

2a = 0.16

a = 0.08

do you have a picture of the table

b

step-by-step explanation: