*PLEASE ANSWER* The softball in the mitt is 5.2 inches in diameter. What is its volume? (Use 3.14)

Step-by-step explanation:

d= 5.2 in

r= 5.2 /2

=2.6 in

the volume we use formula

V= 4/3 × π × r³ (π=3,14)

= 4/3 × 3,14 × (2,6)³

= 4/3 × 3,14 × 17,56

= 73, 6 in³

Hope this helps^°^...

Step-by-step explanation:

d= 5.2 in

r= 5.2 /2

=2.6 in

the volume we use formula

V= 4/3 × π × r³ (π=3,14)

= 4/3 × 3,14 × (2,6)³

= 4/3 × 3,14 × 17,56

= 73, 6 in³

Hope this helps^°^...

73.6 inches cubed.

Step-by-step explanation:

The softball is a sphere. Its diameter is 5.2 inches, which means its radius is 5.2 / 2 = 2.6 inches.

The volume of a sphere is (4/3)pi * r^3.

(4/3) * pi * (2.6)^3

= (4/3) * 3.14 * 17.576

= (4/3) * 55.18864

= 73.58485333.

That means that the softball's volume is about 73.6 inches cubed.

Hope this helps!

73.6 inches cubed.

Step-by-step explanation:

The softball is a sphere. Its diameter is 5.2 inches, which means its radius is 5.2 / 2 = 2.6 inches.

The volume of a sphere is (4/3)pi * r^3.

(4/3) * pi * (2.6)^3

= (4/3) * 3.14 * 17.576

= (4/3) * 55.18864

= 73.58485333.

That means that the softball's volume is about 73.6 inches cubed.

Hope this helps!

is should be y = 5x

step-by-step explanation:

correct me if im wrong