what is the prime factorization of 55^5 x 65 x 9^15 and why? A. 3^15 * 5^6 *11^5*13 B. 3^30 *5^6 *11^5 *13 C.3^30 * 5^6 *11 * 13 D. 3^30 *5^5*11^5*13

B

Step-by-step explanation:

1. Lets focus on 55^5

55^5 = 11^5 * 5^5

2. now on 65

65 = 5 * 13

3. now on 9^15

9^15=(3^2)^15 = 3^30

4. combine all three parts

11^5 * 5^5 * 5 * 13 * 3^30 = 11^5*5^6*13*3^30

so our answer is B

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

idk bring the function back   im not smart

step-by-step explanation: