Given that ΔABC is a right triangle with a right angle at C, if tan A = , find the value for tan B. A. tanB =
B. tanB =
C. tanB =
D. tanB =

C

Step-by-step explanation:

tan A = = , thus

The opposite side is the adjacent side for B and the adjacent side is the opposite side for B, thus

tan B =

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5