The amount of air present in a cylinder when a vacuum pump removes1/4 air remaining in the cylinder at a time. is this an ap?

It is not an ap

Step-by-step explanation:

Step-by-step explanation:

Let a be the amount of air initially Amount of air remaining after 1st pump =a –(a/4)=3a/4

Amount of air remaining after 2nd  pump= (3a/4) – (1/4)(3a/4)=9a/16

Amount of air remaining after 3rd  pump= (9a/16) – (1/4)(9a/16)=27a/64

So the series is like

a,3a/4,9a/4,27a/64……..

Difference Ist and second term=-a/4

Difference between Second and Third term= -3a/16

So difference is not constant

So it is not Arithmetic Progression

It is not an ap

Step-by-step explanation:

Step-by-step explanation:

Let a be the amount of air initially Amount of air remaining after 1st pump =a –(a/4)=3a/4

Amount of air remaining after 2nd  pump= (3a/4) – (1/4)(3a/4)=9a/16

Amount of air remaining after 3rd  pump= (9a/16) – (1/4)(9a/16)=27a/64

So the series is like

a,3a/4,9a/4,27a/64……..

Difference Ist and second term=-a/4

Difference between Second and Third term= -3a/16

So difference is not constant

So it is not Arithmetic Progression

include a picture of the drawing in order for me to

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb