Do phone surveys provide adequate coverage of households with respect to one particular parameter? The parameter is the proportion of households without children. If telephone surveys provide adequate coverage of households, then p , the proportion of households without children in the set of all future samples reached by phone, must be equal to the proportion of households without children in the population of all households. Suppose that Thomas, a market analyst, contacts a simple random sample of 300 households as part of a national telephone survey. Of the households contacted, 129 households, or 43 %, have no children and 57 % have at least one child. The most recent census indicates that 48 % of all households have no children and 52 % have at least one child.

Complete  Question

The complete question is shown on the first uploaded image

Based on the result of his test , Thomas should fail to reject null hypothesis at a significance level of  0.01. Thomas sufficient evidence  to conclude that  the proportion of  households without children in the set of all future samples reached by phone is not equal to the proportion of households without children in the population of all households.

Step-by-step explanation:

From the question we see that the p-value is greater than the level of significance (0.01 )so we fail to reject the null hypothesis.

This means that Thomas has  sufficient evidence to conclude that the proportion of households without children in the set of all future samples reached by phone is not equal to the proportion of households without children in the population of all households.

to rewrite a literal equation you may need to divide by a number, or by a variable.

hope i .

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).