Isabelle bought some stationery.1/3 of them. Were pencils.5/8 of the remainder were erasers and the rest were rulers. The table shows the cost of each stationery, Pencil:$1.20,Eraser:$1,Ruler:$0.50. She spent a total of $169.50 on all the stationery. a)What fraction of the stationery bought was rulers? b)How much more did she spend one erasers than rulers?

1/4 ; $28.25

Step-by-step explanation:

Given the following :

Cost of stationeries:

Pencil:$1.20

Eraser:$1

Ruler:$0.50

Total : $169.50

Let total Stationeries purchased = t

Fraction of pencils = 1/3t

Remainder = t - 1/3 = 2/3t

Fraction of eraser = 5/8 of remainder

Thus ;

Fraction of eraser = 5/8 * (2/3)t= 10/24 = (5/12)t

Rest were ruler ;

(2/3)t - (5/12)t= (8 - 5)/12

= 3 / 12 = 1/4t

Fraction of rulers = 1/4

Amount spent on erasers:

(5/12) of the total cost of stationery

(5/12) * 169.50 = $70.625

B.) How much more did she spend on erasers than rulers

Amount spent on rulers :

(1/4) * $169.50 = $42.375

Take the difference :

$(70.625 - 42.375) = $28.25

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

step-by-step explanation:

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