Kofi and kweku are two brothers. Kofi is older than kweku. Given that kofi's age is (5x-4) years and kweku's age is (2x+1) years. a. write down an expression, interns of x, for how much old is Kofi than kweku.
b. if Kofi is tens years older than kweku, find the value of x and the ages of Kofi and kweku

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Step-by-step explanation:

Given the details :

Kofi is older than kweku

kofi's age = (5x-4) years

kweku's age = (2x+1) years

a. write down an expression, interns of x,for how much old is Kofi than kweku

Equate the ages of Kofi and kweku

(5x - 4) = (2x + 1)

5x - 4 = 2x + 1

5x - 2x = 1 + 4

3x = 5

3x - 5

B.) if Kofi is tens years older than kweku, find the value of x and the ages of Kofi and kweku

Then,

(5x-4) = (2x + 1) + 10

5x - 4 = 2x + 1 + 10

5x - 2x = 1 + 10 + 4

3x = 15

x = 5

Kofi's age : 5x - 4

5(5) - 4 = 25 - 4 = 21 years

Kweku's age : (2x + 1)

2(5) + 1 = 10 + 1 = 11 years

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

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step-by-step explanation: