A certain animal's body temperature has a mean of F and a standard deviation of F. Convert the given temperatures to z scores.

A certain animal's body temperature has a mean of 94.72° F and a standard deviation of 0.57°F. Convert the given temperatures to z scores.

a. 93.52 °F  b. 95.22 °F      c. 94.72 °F

a. z = - 2.1053

b. z = 0.87719

c. z = 0

Step-by-step explanation:

Given that :

The population mean μ = 94.72

The standard deviation σ = 0.57

the formula for calculating the standard normal z score, which can be represented as:

For  a.

The sample mean = 93.52

The z score can be computed as follows:

z = - 2.1053

For  b.

The sample mean  =  95.22    

z = 0.87719

For  c.

The sample mean  = 94.72

z = 0

1.true 2.false? ? i think. .

step-by-step explanation: