The sum of the ages of Noi's and Noy's is 26 years. The different between four times Noi's age and two times Noy's age is 28 years. Find the age of Noi and Noy. WRITE AS AN EQUATION

The age of Noi is 13.333 Years and the age of Noy is 12.67 years

Step-by-step explanation:

The given  information are;

The sum of the ages of Noi and Noy = 26 years

Four times Noi's age - Two times Noy's age = 28

Let the age of Noi = X and let the age of Noy = Y

We have;

X + Y = 26 years(1)

4X - 2Y = 28 years(2)

Divide equation (2) by 2 to get;

(4X - 2Y)/2 = (28 years)/2 which gives;

2X - Y = 14 years(3)

Add equation (3) to equation (1), to get;

X + Y +  2X - Y = 26 years + 14  years

3X = 40 years

X = 40/3 = 13.333 Years

From equation (1), X + Y = 26 years, therefore;

Y = 26 - X = 26 - 13.33 = 12.67 years

Therefore, the age of Noi = 13.333 Years and the age of Noy = 12.67 years.

answer: entity is prob the answer

step-by-step explanation: