the the diameter of a circular Garden is 140 metre . On its outside there is a road of 7 metre wide find out the outer circumference of the road

484 meters

Step-by-step explanation:

diameter of a circular Garden = 140 metre

we know diameter = 2*radius

140 = 2*radius

radius = 140/2 = 70 meter

thus, radius of garden is 70 meter

Given that

On its outside there is a road of 7 metre wide

Thus, radius of garden along-with road will increase by 7 meters

Total radius of garden and road = 70 meter + 7 meter = 77 meter

 outer circumference of the road can be calculated using radius 77 meter.

we know that circumference =

we will use value of

Thus, outer circumference of the road with radius 77 m

=

Thus,

The outer circumference of the road is 484 meters.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb