Arnold made the following grades on his quizzes and assignments: 80, 92, 88, 90, 75, 38, 92, 95 2. Arnold wants to present his scores as advantageously as possible. Should he use the mean or the median of this data set? What other strategies could he employ to yield a more favorable measure of center?

Step-by-step explanation:

If he were to find the mean then he would need to add all the numbers up and divide by the number of numbers. The answer of this would 69.1

If you find the median you would need to put the numbers in order,

2, 38, 75, 80, 88, 90, 92, 92, 95, then find the middle which would be 88.

So the better option would be finding the median. I think that this would be the best way to get the the most favorable measure of center.

I hope this helps.

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm