Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40°. Building A is 120 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet? Building A; it is around 100.69 feet taller than building B Building A; it is around 50.34 feet taller than building B Building B; it is around 100.69 feet taller than building A Building B; it is around 50.34 feet taller than building A

Building A is taller. it is around 50.34 feet taller than building B

Step-by-step explanation:

Refer the attached figure

We are given that Kayson is looking at two buildings,building A and building B, at an angle of elevation of 40°.

Building A is 120 feet away.

BC =120 feet

Building B is 60 feet away.

BE= 60 feet

In ΔABC

In ΔDBE

50.34=DE

Difference between their heights=100.68-50.34=50.34

So, Building A is taller. it is around 50.34 feet taller than building B

(3x-8) or (3x+8)

step-by-step explanation:

replace   with   27   and simplify.

10 , 27 , 10 , 70 , 10 , 35 , 10 , 48

step-by-step explanation: