The population of a town increases 10% every 3 years if the present population is 72600 calculate its population after 6 years and 6 years ago

After 6 years = 87120 people.

Before 6 years = 5808 people.

Step-by-step explanation:

To calculate how many populations that are added in every 10% in 3 years:

72600 × 10/100 = 7260

After 6 years = 72600 + 7260 × 2 = 87120 people.

Before 6 years = 72600 - 7260 × 2 = 5808 people.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.