Alexander bought a box of crackers at the store. He ate half of the crackers in the box on Monday, and he ate 1/2 of what was left on Tuesday. On Wednesday, he ate 1/3 of what was left after he was finished eating the crackers on Tuesday. 1) What fractional part of the total crackers originally in the box did Alexander
eat on Wednesday?
2) what fractional part of the total crackers originally in the box are left. 3) if there are 4 crackers left in the box after Alexander finished eating crackers on wensday, how many crackers were in the box before it was opened. (Please help!)

Given the equivocal nature of this question, I will need to draw an assumption: I will assume that Ali ate from the cake and so did Jason — not Ali ate from the cake and Jason ate from Ali’s slice.

With that being said, the first approach is make both of these fractions have a common denominator, so that we can find how much each respective person ate from the total amount of slices. Intuitively, the common denominator is 12

12

, so this must be true:

Ali ate 4/12

4

/

12

of the cake;

Jason ate 3/12

3

/

12

of the cake

Adding these two fractions will give us 7/12

7

/

12

— the total amount eaten. Now, to find the amount left, we need only subtract 7/12

7

/

12

from 12/12

12

/

12

(the total amount of the cake). Doing so will give us

Step-by-step explanation:

answer: ur v dumb

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°