X + 3y = 42
2x - y= 14

x=12,y=10

Step-by-step explanation:

Step: Solve x+3y=42

x+3y=42

x+3y+−3y=42+−3y(Add -3y to both sides)

x=−3y+42

Step: Substitute−3y+42forxin2x−y=14:

2x−y=14

2(−3y+42)−y=14

−7y+84=14(Simplify both sides of the equation)

−7y+84+−84=14+−84(Add -84 to both sides)

−7y=−70

Divide both sides by -7

y=10

Step: Substitute10foryinx=−3y+42:

x=−3y+42

x=(−3)(10)+42

x=12(Simplify both sides of the equation)

Hope this Helps:)

-Ac<3-

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true