Segment YW is an altitude of triangle XYZ. Find the area of the triangle. Triangle XYZ with altitude YW is shown. Point X is at 5, negative 3. Point Y is at 8, negative 1. Point Z is at 5, 4. Point W is at 5, negative 1. 7.5 9.5 10.5 15

The correct option is;

10.5

Step-by-step explanation:

The given coordinates are;

Triangle XYZ

Coordinates of X = (5, -3)

Coordinates of Y = (8, -1)

Coordinates of Z = (5, 4)

Coordinates of point W = (5, -1)

Given that W is on segment XZ, we have;

Length of segment XZ = A base of the triangle is given by the relation;

Where

(x₁, y₁) = (5, -3)

(x₂, y₂) = (5, 4)

Therefore, we have;

= 7

The length of segment YW is also given as follows;

Given that the height of the triangle XYZ is given by segment  YW, the area of triangle XYZ = 1/2 × Base × Height = 1/2×7×3 = 21/2 = 10.5

The area of triangle XYZ  = 10.5.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

answer:   y=2x-3

step-by-step explanation: