Show that (a - b)+(b-c)+(c -a)3 = 3 (a - b) (b -c) (c-a)

I think that it should be

Step-by-step explanation:

Here,

we take , a - b = A,b-c = B , c - a= C

A+B+C = 0

we know that,

Here , A+B+C = 0

so,

A^3 +B^3 + C^3 = 3 ABC

now we put the values

I am done .

b or 2, just plug these equations into your graphing calculator then check the graph to see the image. if it matches up then that's your answer!

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24