What is the area of this triangle? Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth.

Greetings from Brasil...

We need to use the Cosine Law in Any Triangle, so we can use Heron's formula.

AC² = AB² + BC² - 2.AB.BC.COS B

AC² = 11² + 9² - 2.11.9.COS 63

AC ≈ 10,63

Heron's Formula:

Area = √[P.(P - AB).(P - BC).(P - AC)]

where P = (AB + BC + AC)/2

P = (11 + 9 + 10,63)/2 ⇒ P ≈ 15,31

Area = √[15,31.(15,31 - 11).(15,31 - 9).(15,31 - 10,63)]

the answer is 0.071

good luck! : d