A small triangular lot has three sides of different length. The second side is 11 feet longer than the first side. The third side is 8 feet less than twice the first side. The perimeter of the lot is 71 feet. How long is the third side? A) 28 ft
B) 38 ft
C) 17ft
D) 26ft

first side = 17 ft

second side = 28 ft

third side = 26 ft

Step-by-step explanation:

a + b + c  = 71

b = a + 11

c = 2a - 8

a = first side lenght

b = second side lenght

c = third side lenght

a + (a+11) + (2a-8) = 71

4a + 11 - 8 = 71

4a + 3 = 71

4a = 71 - 3

4a = 68

a = 68/4

a = 17

b = a + 11

b = 17 + 11

b = 28

c = 2a - 8

c = 2*17  -  8

c = 34 - 8

c = 26

Check:

17 + 28 + 26 = 71

stop using this to cheat on home work

step-by-step explanation:

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b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !