If sin theta = 4/5 and cos theta is in quadrant II, then cos theta and tan theta equal what?

In quadrant ll,

cos theta = -3/5

tan theta = -4/3

Step-by-step explanation:

In quadrant ll, only sin is positive, cos and tan are negative

sin theta = opposite/hypotenuse = 4/5

From Pythagoras theorem,

adjacent = sqrt(hyp^2 - opp^2) = sqrt(5^2 - 4^2) = sqrt(25 - 16) = sqrt(9) = 3

cos theta = adjacent/hypotenuse = -3/5

tan theta = opposite/adjacent = -4/3

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