Alyssa bought a paperweight in the shape of a cone. The radius was 10 centimeters and the height 9 centimeters. What's the volume of the paperweight?

300 pi, 942, or 942.477... cm^3

Step-by-step explanation:

The volume of a cone can be found using the following formula.

V= 1/3* pi* r^2* h

We know that the radius is 10 centimeters and the height is 9 centimeters.

r= 10 cm

h= 9 cm

V= 1/3* pi * (10 cm)^2 * 9 cm

First, evaluate the exponent.

(10 cm)^2= 10 cm * 10 cm = 100 cm^2

V= 1/3 * pi * 100 cm^2 * 9 cm

In terms of pi:

To solve in terms of pi, multiply all the terms that are not pi together

V= (1/3* 100 cm^2*9cm)*pi

V= (1/3* 900 cm^3)*pi

V= (300 cm^3)* pi

V= 300 pi cm^3

Using 3.14 as pi

V= 300 pi cm^3

Substitute 3.14 in for pi

V= (300*3.14) cm^3

V= 942 cm^3

Using 3.14159265 as pi

V= 300 pi cm^3

Use the pi button for pi

V= 942.477796076938 cm^3

The volume of the paperweight is 300 pi, 942, or 942.477796... cm^3

942.5 cm³

Step-by-step explanation:

pi r²h/3

π(10)²(9)/3 = 942.5 cm³

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.