Five thousand dollars is deposited into a savings account at 2.5% interest compounded continuously. a. What is the formula for A(t), the balance after t years?

b. What differential equation is satisfied by A(t), the balance after t years?

c. How much money will be in the account after 5 years? (Do not round until your final answer. Round your final

answer to the nearest cent as needed.

d. When will the balance reach $7,000? (Do not round until your final answer. Round your final answer to the

nearest tenth as needed.)

A). A(t) = P(1+r/n)^(nt)

B). DA/Dt = np(1+r/n)^(t)

C). A(5) =$ 5664.0

D).t = approximately 13.5 years

Step-by-step explanation:

A(t) = P(1+r/n)^(nt)

P = $5000

n= t

r= 2.5%

After five years t = 5

A(t) = P(1+r/n)^(nt)

A(5) = 5000(1+0.025/5)^(5*5)

A(5) = 5000(1+0.005)^(25)

A(5)= 5000(1.005)^(25)

A(5) = 5000(1.132795575)

A(5) = 5663.977875

A(5) =$ 5664.0

When the balance A= $7000

A(t) = P(1+r/n)^(nt)

7000= 5000(1+0.025/n)^(nt)

But n= t

7000= 5000(1+0.025/t)^(t²)

7000/5000= (1+0.025/t)^(t²)

1.4= (1+0.025/t)^(t²)

Using trial and error

t = approximately 13.5 years

because they could drop even lower..

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.