For what values of a the following expressions are true: |a−5|=5−a

Whenever  .

Step-by-step explanation:

We can play around with some numbers and develop some rules for this equation.

Note that the number 5 and -5 are used here, so let's try using 5 as a.

So 5 works. Let's try a random number like 3.

Okay, with this info we know that we might be able to develop one rule that . Just to test, let's try 0, -3, and -5.

Zero works.

-3 works.

-5 works. Now, this might stop here making the equation , so let's test a number outside of -5 - say -20.

Yes! This works, so a works for this equation as long as .

Hope this helped!

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)