Suppose 45% of the worlds population has type "O" blood type. A study was done to see if the percent differs for college students. 47% of the 1000 random selected college students have type O blood. conduct a hypothesis test to determine if the percent of college students with type o blood differs for college students?

We accept H₀, with CI = 90 %, porcentage of O blood type in college students does not differ from the world population porcentage

Step-by-step explanation:

The test is a proportion  two-tail test ( note: differs)

p₀ = 45 %      or  p₀ = 0,45

n = 1000

p =  47 %        or  p  = 0,47

Test Hypothesis

Null hypothesis                                H₀                   p  =  p₀

Alternative hypothesis                    Hₐ                   p  ≠ p₀

CI  we assume 90 %  then  α = 10 %    α  =  0,1    α/2  = 0,05

z score  from z-table   z(c) = 1,64

To calculate z(s) = ( p - p₀ ) / √ p₀q₀/ n

z(s)  = ( 0,47  -  0,45 )/ √( 0,45)*(0,55)/1000

z(s)  =  0,02/√( 0,2475)/1000

z(s)  =  0,02/0,01573

z(s) = 1,2714

Now we compare z(s) and z(c)

z(s) < z(c)      1,2714 < 1,64

Then z(s) is in the acceptance region we accept H₀

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

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