The function h(x) is a translation of the exponential function g(x) = 9(1∕6)x. What's h(x) if the translation is a vertical shrink by a factor of 1∕3 and horizontal shift to the left 4 units?

h(x) = 3*(1/6)^(x + 4)

Step-by-step explanation:

if we have a function g(x), and we want to create another function h(x) such that:

h(x) is a vertical contraction/dilation of factor a.

Then h(x) = a*g(x).

h(x) is a right shift of N units (N positive):

h(x) = g(x - N)

Then:

A vertical shink of factor 1/3 means that:

h(x) = (1/3)*g(x)

And a left shift of 4 units (or a right shift of -4 units) means that

h(x) = (1/3)g(x - (-4)) = (1/3)*g(x + 4)

and we know that:

g(x) = 9*(1/6)^x

Then:

h(x) = (1/3)*9*(1/6)^(x + 4) = 3*(1/6)^(x + 4)

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answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0