i have tried everything At Central Online High School, 45100 of the students have a dog, 30100 of the students have a cat, and 18100 of the students have both a dog and a cat. What is the probability that students who have a cat also have a dog?

Work Shown:

Let's say this school has 100 people total. We know that 30 of the people have a cat since 30/100 is the fractional portion of cat owners. Similarly, 18 have both a cat and a dog.

The probability of selecting someone who has both pets, given we know they are a cat owner, is 18/30 = 3/5

To reduce the fraction, divide both parts by the GCF 6.

Note: we don't use 45/100 because we know that whoever selected wasn't solely a dog owner.

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2