Find the area of a 2-inch-wide decorative border around a rectangular canvas painting, where L is the length and W is the width of the canvas painting. (Formula for area of a rectangle: A equals L times W)

  4L +4W +16 square inches

Step-by-step explanation:

The area of the border is the equivalent of that of a rectangle with a width equal to the width of the border, and a length equal to the length of the midline of the border. That length is the perimeter of the rectangle that is L+2 units long and W+2 units wide.

  border midline length = 2((L+2) +(W+2)) = 2L +2W +8

Then the border area is ...

  border area = (border width)(border length) = (2)(2L +2W +8)

  border area = 4L +4W +16 . . . square inches

You can also figure this as the difference between the area of the rectangle with the border and the area of the rectangle inside the border:

  border area = total area - canvas area

  = (L+4)(W+4) -LW = LW +4L +4W +16 -LW

  = 4L +4W +16 . . . . square inches

y=mx+b

step-by-step explanation:

m slope, b y-intercept

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn