Given: AB ∥ DC , m CB =62°, m∠DAB=104° Find: m∠DEA, m∠ADB

m∠DEA = 62° and m∠ADB = 318°

Step-by-step explanation:

, - (Given)

m∠CB = 62° (Given)

we have;

m∠CB ≅ m∠DA (parallel lines congruent arc theorem)

m∠DA = 62° = m∠DEA

m∠DAB = 104° Given

Therefore, m∠AB = 104° - 62° = 42° (sum of angle)

m∠DC = 360 - 62 - 62 - 42 = 194°  (sum of angles around a circle)

m∠ADB = 360° - m∠AB (sum of angles around a circle)

Therefore, m∠ADB = 360° - 42° = 318°

The required angles are;

m∠DEA = 62° and m∠ADB = 318°

you can't solve x because it is 2 linear equation and you only have one equation

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0