Which equation is the inverse of y = 16x2 + 1? y = plus-or-minus StartRoot StartFraction x Over 16 EndFraction minus 1 EndRoot y = StartFraction plus-or-minus StartRoot x minus 1 EndRoot Over 16 EndFraction y = StartFraction plus-or-minus StartRoot x EndRoot Over 4 EndFraction minus one-fourth y = StartFraction plus-or-minus StartRoot x minus 1 EndRoot Over 4 EndFraction

The inverse is ±sqrt((x-1))/ 4

Step-by-step explanation:

y = 16x^2 + 1

To find the inverse, exchange x and y

x = 16 y^2 +1

Then solve for y

Subtract 1

x-1 = 16 y^2

Divide by 16

(x-1)/16 = y^2

Take the square root of each side

±sqrt((x-1)/16) = sqrt(y^2)

±sqrt((x-1))/ sqrt(16) = y

±sqrt((x-1))/ 4 = y

The inverse is ±sqrt((x-1))/ 4

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

a ≈ 172.05

step-by-step explanation:

the pictures.