Help again 《Brainlist》 A six faced dice with numbers 1 thru 6 is thrown twice. No fee is charges to the throws. If the organizer of the game has to payout as many dollars as the result every time an even sum comes up and will receive from the player as many dollars as the result if the sum is odd, in the very long run, when 1 million throws are made,
approximately how much is the winning or loss to the organizer?

win-263889 loss-236111

Step-by-step explanation:

1:the guys throws the dice twice no charge for this

2:for every face the first time there is a chance of getting the others or the same face e.g round 1-1 round 2-(either 123456)

3:I drew a probability tree to get the sum

like if I got 1and1 then sum is 2 I did it for the rest

4:I got P of (even)=17/36 and for (odd)=19/36

5:then the organizer has to pay if it's even and there 1 million throws Wich means the probability he will lose is the probability of getting an even sum for 500000 throws and for winning is the probability of getting odd sums in those 500,000 throws

6: 500k is because only after it's thrown twice were there charges

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)