2. Suppose that the mean salary in a particular profession is $45,000 with a standard deviation of $1,500. What percentage of people in that profession earn less than $48,000

93%

Step-by-step explanation:

mean=45,000 standard deviation=2000 value of concern=48,000

We can easily see that since the value of concern (48,000) is GREATER than the mean, we can rule out the last two choices.

There is no possible way a number can be greater than the mean, but less than the 50th percentile.

convert 48,000 into a z-score, which is given as:

(x-mean)/standard deviation

or in this case:

(48000-45000)/2000=1.5

using my z-score table or calculator, I can see that a z-score of 1.5 corresponds to about the 93th percentile

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

i need points

step-by-step explanation:

sorry bubs