Based on historical data, an insurance company estimates that a particular customer has a 2.6% likelihood of having an accident in the next year, with the average insurance payout being $1600. If the company charges this customer an annual premium of $110, what is the company's expected value of this insurance policy?

$68.4

Step-by-step explanation:

Given: Annual Premium = $110

Average insurance payout = $1600

Likelihood of having an accident= 2.6% = 0.026 [we divide perecnt by 100 to convert it into decimal]

Then, Expected value = (Annual Premium) - (Likelihood of having an accident) x (Average insurance payout )

= $110  - (0.026) x ($1600)

= $(110-41.6)

= $68.4

Hence, the company's expected value of this insurance policy : $68.4

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

the answer is 0.000652422

but if you ment to ask what is 6131 divided by 4, it is 1532.75.

step-by-step explanation: