Mathematics, 29.07.2020 03:01 mailani12503
① 5J+2S =12.20 ② 5J+ 10S =15.80 elimination method
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Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
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The depth of a lake at a certain point, wich is a function of the distance of that point from shore, is 30 feet.
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Plz.yesterday, the snow was 2 feet deep in front of archie’s house. today, the snow depth dropped to 1.6 feet because the day is so warm. what is the percent change in the depth of the snow?
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① 5J+2S =12.20 ② 5J+ 10S =15.80 elimination method...
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