Mathematics, 29.07.2020 15:01 JOEREACH
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, -6), B(5, -6), C(5, -2) and D(2, -2). What is the perimeter of rectangle ABCD?
Answers: 1
![AB =\sqrt{(5-2)^{2}+(-6-[-6])^{2}}\\\\=\sqrt{(5-2)^{2}+(-6+6)^{2}}\\\\=\sqrt{3^{2}+0}\\\\=\sqrt{3^{2}}\\\\=3 units\\](/tpl/images/0714/8007/80084.png)
![BC = \sqrt{(5-5)^{2}+(-2-[-6])^{2}}\\\\ = \sqrt{0+(-2+6)^{2}}\\\\ = \sqrt{4^{2}}\\\\](/tpl/images/0714/8007/d1ca8.png)
![CD = \sqrt{(2-5)^{2}+(-2-[-2])^{2}}\\\\ = \sqrt{(-3)^{2}+(-2+2)^{2}}\\\\ = \sqrt{(-3)^{2}}](/tpl/images/0714/8007/c3f38.png)
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Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle:...
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