What are the coordinates of the vertex of the function f(x)=x2+ 10x-3? O (-5. -28)
(-5, 28)
O (5,-28)
(5.28)

 A.  (-5, -28)

Step-by-step explanation:

f(x) = x² + 10x - 3

     a=1    b=10  

The axis of symmetry is the x-coordinate of the vertex:

Input x = -5 into the original equation to find the y-coordinate of the vertex:

f(-5) = (-5)² + 10(-5) - 3

      =  25      -50    -3

      = -28

x, y coordinate of the vertex is: (-5, -28)

cheater

step-by-step explanation:

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7