Find the probability of rolling a three first and then a ten when a pair of dice is rolled twice

0.0046

Step-by-step explanation:

First, let's calculate the total number of outcomes that you can see from a pair of dice.

Each dice has 6 options, so the total number of combinations is:

6*6 = 36.

Now, the combinations that are equal to 3 are:

3 and 1

1 and 3

2 combinations.

So the probability is equal to the quotient between the number of combinations that are equal to 3, and the total number of combinations:

P = 2/36 = 0.055

Now, the combinations that are equal to 10 are:

5 and 5

4 and 6

6 and 4.

3 combinations.

Then the probability is:

P = 3/36 = 0.0833

Now, the probability of both events happening is equal to the product of the probabilities for each event, so the total probability is equal to:

P = ( 0.0833)*( 0.055) = 0.0046

yor answer is 7/6 times 5

step-by-step explanation:

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply