If ABCD is a parallelogram, AD = 14, EC = 11, mZABC = 64°, mZDAC = 71°, and mZBDC = 25, find each measure.
А
a) BC =
d) mZABD =
B
b) AC =
e) m ACD =
E
D
С
c) m DAB
f) mZADB =

a) BC = 11

b) AC = 22

c) m∠DAB = 116°

d) m∠ABD = 39°

e) m∠ACD = 45°

f) m∠ADB = 25°

Given : AD=14 , EC=11, m∠ABC= 64°, m∠DAC=71° and m∠BDC=25°

To find:  BC =?  , AC =? , m∠DAB =?, m∠ABD =?  ,m∠ACD =?  ,m∠ADB =?

Consider the figure given below ABCD is a parallelogram

To find a) BC

Given, EC = 11

As seen in figure that EC and BC are equal sides of a diagonal line that has been divided into two equal parts in a Parallelogram.

Hence, In a Parallelogram ABCD,

EC = BC

Hence BC = 11

To find b) AC

AC is one of the diagonal lines that divided parallelogram ABCD

AC = BC + EC

AC = 11 + 11

AC = 22

To find c) m∠DAB

Given, m∠ABC = 64°

m∠ADC = 64°

(For the two angles above, a diagonal bisects through those angles)

Also From Angle sum property;

Hence,

180° = 1/2m∠ABC + 1/2m∠ADC +  m∠DAB

m∠DAB = 180° - ( 1/2 (64) + 1/2(64))

m∠DAB = 180 ° - 64°

m∠DAB = 116°

To find d) m∠ABD

Since,

m∠ABC = 64° and m∠BDC = 25  

m∠ABC = m∠BDC + m∠ABD

64 = 25+ m∠ABD

m∠ABD = 64° - 25°

m∠ABD = 39°

To find e) m∠ACD

Given,  m∠ABC = 64°;

m∠ADC = m∠ABC, this is because, opposite angles in a quadrilateral (here parallelogram) are congruent and equal to each other

Hence, m∠ADC = 64°

m∠DAC = 71°,

In a triangle , all the angles in a triangle = 180°(Angle sum property)

Hence,

180° = m∠DAC + m∠ADC + m∠ACD

180° = 71° + 64 ° + m∠ACD

m∠ACD = 180° - (71 + 64)°

m∠ACD = 180° - 135°

m∠ACD = 45°

To find f) m∠ADB

Since  ,m∠DAB = 116°  and m∠ABD = 39°

From Angle sum property;

180° = m∠ABD + m∠DAB + m∠ADB

180° = 39 ° + 116° + m∠ADB

m∠ADB = 180° - ( 116 + 39)°

m∠ADB = 25 °

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Find attached to this answer the diagram of the Quadrilateral

Question:

If ABCD is a parallelogram, AD = 14, EC = 11, m∠ABC = 64°, m∠DAC = 71°, and m∠BDC = 25, find each measure.

a) BC =

b) AC =

c) m∠DAB =

d) m∠ABD =

e) m∠ACD =

f) m∠ADB =

a) BC = 11

b) AC = 22

c) m∠DAB = 116°

d) m∠ABD = 39°

e) m∠ACD = 45°

f) m∠ADB = 25°

Step-by-step explanation:

a) BC

In the question above, EC = 11

We can see that EC and BC are equal sides of a diagonal line that has been divided into two equal parts in a Quadrilateral.

Hence, In a quadrilateral ABCD,

EC = BC

Hence BC = 11

b) AC

AC is one of the diagonal lines that divided parallelogram ABCD

AC = BC + EC

AC = 11 + 11

AC = 22

c) m∠DAB

m∠ABC = 64°

m∠ADC = 64°

For the two angles above, a diagonal bisects through those angles.

Also the sum of angles in a triangle = 180°

Hence,

180° = 1/2m∠ABC + 1/2m∠ADC +

m∠DAB

m∠DAB = 180° - ( 1/2 (64) + 1/2(64))

m∠DAB = 180 ° - 64°

m∠DAB = 116°

d) m∠ABD

Since,

m∠ABC = 64° and m∠BDC = 25

m∠ABC = m∠BDC + m∠ABD

64 = 25+ m∠ABD

m∠ABD = 64° - 25°

m∠ABD = 39°

e) m∠ACD

In the above question,

m∠ABC = 64°,

m∠ADC = m∠ABC, this is because, opposite angles in a quadrilateral are congruent and equal to each other.

Hence, m∠ADC = 64°

m∠DAC = 71°,

In a triangle , all the angles in a triangle = 180°

Hence,

180° = m∠DAC + m∠ADC + m∠ACD

180° = 71° + 64 ° + m∠ACD

m∠ACD = 180° -(71 + 64)°

m∠ACD = 180° - 135°

m∠ACD = 45°

f) m∠ADB

Since

m∠DAB = 116°

m∠ABD = 39°

The sum of angles in a triangle = 180°

180° = m∠ABD + m∠DAB + m∠ADB

180° = 39 ° + 116° + m∠ADB

m∠ADB = 180° - ( 116 + 39)°

m∠ADB = 25 °

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