Six identical coins are tossed. How many possible arrangements of the coins include three heads and three tails?

The possible arrangement= 18 ways

Step-by-step explanation:

Six identical coin are tossed.

Coin has only a tail and a head.

In how many possible ways can the arrangement be 3 head and 3 tail.

The possible arrangement= (3! * 3!)/2

The reason for dividing by two because coin has two face.

The possible arrangement= (3! * 3!)/2

The possible arrangement=( 6*6)/2

The possible arrangement= 36/2

The possible arrangement= 18 ways

probability for j is 1/4

while

a is 1/6

step-by-step explanation:

hunhgunyt7 in u uuuhiuteu