Raina, Justin, and cho have $79 in their wallets. Raina has $5 leas than Justin. Cho has 2 times what Justin has. How much does each have?

Hey there! I'm happy to help!

Let's represent everybody with variables. Raina is R, Justin is J, and Cho is C. Let's write down this information as a system of equations.

R+J+C=79            (they all have 79 total dollars in their wallets combined)

R=J-5                    (Raina has five less than Justin.)

C= 2J                        (Cho has twice that of Justin)

Since we know what R and C equal, we can plug in their values in terms of J into the first equation to solve for J.

J-5+J+2J=79

We combine like terms.

4J-5=79

We add 5 to both sides.

4J=84

We divide both sides by 4.

J=21

This means that Justin has $21. If Raina has 5 less, she has $16 and since Cho has twice that of Justin he has $42. These added up equal 79.

I hope that this helps! Have a wonderful day!

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18