((Please help asap! Giving brainliest)) Write an equation of a line perpendicular to line CD below in slope-intercept form that passes through the point (−1, 6).
Line CD is shown. C is at 1, 1. D is at 3, 5.

Select one:

a. y = −0.5x − 5.5

b. y = −0.5x + 5.5

c. y = 2x + 13

d. y = 2x − 13

b. y = −0.5x + 5.5

Step-by-step explanation:

Well first we need to find the slope of line CD.

To do that we'll use the following formula,

We'll use the points (1,1) and (3,5)

So y2 is 5 y1 is 1 so 5-1 = 4

3-1 = 2

Slope = 2x

If the slope of line CD is 2x we can cross out choices C and D.

Two lines that are perpendicular to each other have reciprocal slopes,

meaning is the slope of line CD is 2 then its perpendicular lines slope should be -.5.

If the perpendicular line goes through point (-1,6), the y intercept would be, 5.5.

Look at the image below ↓

Thus,

the answer is option b. y = −0.5x + 5.5.

Hope this helps :)

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.