The surface area of a solid is 10 square feet. The dimensions of a similar solid are three times as great as the first. The surface area of the new solid in square feet
is...
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The total surface area of the new solid in square feet is 90 square feet

Let the solid be a cube.

The surface area of a cube = 6L²

L is the length o the cube;

If the surface area of a solid is 10 square feet, then;

10 = 6L²

L² = 10/6

L = √10/6

If the dimensions of a similar solid are  three times as great as the first, then;

New length Ln = 3√10/6

Total surface area of the new solid = 6Ln²

Total surface area of the new solid = 6(3√10/6)²

Total surface area of the new solid = 6(9*10/6)

Total surface area of the new solid = 6(90/6)

Total surface area of the new solid = 90 square feet

This shows that the total surface area of the new solid in square feet is 90 square feet

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90 ft²

Step-by-step explanation:

Given the sides of similar figures in the ratio a : b, then

ratio of areas = a² : b²

Here ratio of sides = 1 : 3 , thus

ratio of areas = 1² : 3² = 1 : 9

That is the surface area of the new solid is 9 times the first

SA = 9 × 10 = 90 ft²

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0