Find the zeros of y=x^2+4x-9 by completing the square.

Step-by-step explanation:

Let y = 0

0 = x^2+4x-9

x² + 4x -9 = 0

Add 9 on both sides.

x² + 4x = 9

(b/2)² = (4/2)² = 2² = 4

Add 4 on both sides.

x² + 4x + 4 = 13

Facror left side.

(x+2)² = 13

Take the square root on both sides.

x + 2 = ±√13

Subtract 2 on both sides.

x = ±√13 - 2

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

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