Select the table of values where the quadratic function changes direction at a different value of x than the others. A. x -3 -2 -1 0 1 2 3 y 2 3 2 -1 -6 -13 -22 B. x -3 -2 -1 0 1 2 3 y 1 -1 1 7 17 31 49 C. x -3 -2 -1 0 1 2 3 y 4 3 4 7 12 19 28 D. x -3 -2 -1 0 1 2 3 y 28 19 12 7 4 3 4

the answer is c

step-by-step explanation:

10 you would take 50/ .2

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this