Point D is the incenter of triangle BCA. If m∠FHG = 61°, what is the measure of ∠FDG? Triangle BCA with inscribed circle D. Segments BF and BH, CF and CG, and AG and GH are tangent to circle D; segments FD, GD, FH, and GH are created from points F, G, D, and H. 30° 112° 61° 122°

∠FDG = 122° (D)

Step-by-step explanation:

Find attached the diagram obtained from the given information

m∠FHG = 61°

m∠FHG is an inscribed angle and ∠FDG is a central angle

An inscribed angle is half of a central angle.

m∠FHG = 1/2 × ∠FDG

To determine the measure of ∠FDG,

∠FDG = 2× m∠FHG

∠FDG = 2× 61°

∠FDG = 122°

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25

150

step-by-step explanation:

(sorry i'm not typing it again just read the other two explanation sections i just typed it'll be the same.)