Solve the question.
log₃2 log₃(x-4)=1

Solve the equation

log₃2 + log₃(x-4)=1

x = 11/2

Step-by-step explanation:

To solve this, we will follow the steps below:

log₃2 log₃(x-4)=1

applying  the rules of logarithm, logₐ b +   logₐ c  = logₐ(bc)

our equation becomes

log₃2+ log₃(x-4)=1

log₃(2)(x-4) = 1

Also log₃3 = 1

so we will substitute 1 by log₃3  in the equation

log₃(2)(x-4) =  log₃3

2(x-4) = 3

2x -8 = 3

add 8 to both-side of the equation

2x -8 + 8 = 3 + 8

2x = 11

divide both-side of the equation by 2

x = 11/2

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )