Parallel lines p and q are cut by transversal r. On line p where it intersects with line r, 4 angles are created. Labeled clockwise, from the uppercase left, the angles are: 1, 2, 4, 3. On line q where it intersects with line r, 4 angles are created. Labeled clockwise, from the uppercase left, the angles are: 5, 6, 8, 7. m∠3 is (3x + 4)° and m∠5 is (2x + 11)°. Angles 3 and 5 are . The equation can be used to solve for x. m∠5 = °

77 degrees

Step-by-step explanation:

The diagram is drawn and attached below.

m∠3= (3x + 4)°

m∠5 = (2x + 11)°

Angles 3 and 5 are co-interior angles and are therefore supplementary (add up to 180 degrees).

(3x + 4)°+(2x + 11)°=180°

5x+15=180

5x=180-15

5x=165

x=33

Therefore, the measure of angle 5

m∠5 = (2x + 11)°

= (2(33) + 11)°

=66+11

=77°

The measure of angle 5 is 77 degrees.

Question: m∠3 is (3x + 4)° and m∠5 is (2x + 11)°.

Angles 3 and 5 are same side interior angles.

The equation (3x + 4) + (2x + 11) =180 can be used to solve for x.

m∠5 = 77°

x^5/3y^1/3 the correct answer

hope it

false

step-by-step explanation: