Find the area of triangle whose vertices are (- 8,4 )(- 6,6) and (- 3,9)

Area of the triangle = 0

Step-by-step explanation:

We are given the vertices of a triangle as: (- 8,4 ), (- 6,6), (- 3,9)

The formula to find the Area of the triangle =

1/2[ x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]

Where :

(x₁, y₁) =  (- 8,4 )

(x₂, y₂) = (- 6,6)

(x₃, y₃) =  (- 3,9)

Area of the triangle = 1/2[-8(6 - 9) + -6(9 - 4) + -3(4 - 6)]

= 1/2[ (-8 × -3) +( -6 × 5) +( -3× -2)]

= 1/2[ 24 - 30 + 6)

= 1/2[ 24 + 6 - 30]

= 1/2 [30 - 30]

=1/2[ 0 ]

= 0

Therefore, the area of triangle whose vertices are (- 8,4 ), (- 6,6) and (- 3,9) is ZERO( = 0 )

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315

4x and 6y

im not sure though