A bag contains 1 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the probability both beads drawn are green.
6
~
7

9/16

Step-by-step explanation:

There are 4 beads in the bag, 1 purple and 3 green

P ( green) = green/total

                = 3/4

The bead is replaced

There are 4 beads in the bag, 1 purple and 3 green

P ( green) = green/total

                = 3/4

P ( green, replace, green) =P( green) * P ( green)

                                           = 3/4 * 3/4

                                            = 9 /16

a=r

d=q

c=p

b=s

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step-by-step explanation: